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60x+10x^2=10000
We move all terms to the left:
60x+10x^2-(10000)=0
a = 10; b = 60; c = -10000;
Δ = b2-4ac
Δ = 602-4·10·(-10000)
Δ = 403600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{403600}=\sqrt{400*1009}=\sqrt{400}*\sqrt{1009}=20\sqrt{1009}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-20\sqrt{1009}}{2*10}=\frac{-60-20\sqrt{1009}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+20\sqrt{1009}}{2*10}=\frac{-60+20\sqrt{1009}}{20} $
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